7^(6x^2+7)=(1/49)^x

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Solution for 7^(6x^2+7)=(1/49)^x equation: 



7^(6x^2+7)=(1/49)^x

We move all terms to the left:

7^(6x^2+7)-((1/49)^x)=0



Domain of the equation: 49)^x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

7^(6x^2+7)-((+1/49)^x)=0

We multiply all the terms by the denominator


(7^(6x^2+7))*49)^x)-((+1=0

We move all terms containing x to the left, all other terms to the right

(7^(6x^2+7))*49)^x)-((=-1

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